-6x^2=18x

Solution for -6x^2=18x equation:

-6x^2=18x

We move all terms to the left:

-6x^2-(18x)=0

a = -6; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·(-6)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*-6}=\frac{0}{-12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*-6}=\frac{36}{-12}
=-3
$